25y^2=((100-4x^2)/4)

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Solution for 25y^2=((100-4x^2)/4) equation:


x in (-oo:+oo)

25*y^2 = (100-(4*x^2))/4 // - (100-(4*x^2))/4

25*y^2-((100-(4*x^2))/4) = 0

25*y^2-((100-4*x^2)/4) = 0

(-1*(100-4*x^2))/4+25*y^2 = 0

(-1*(100-4*x^2))/4+(4*25*y^2)/4 = 0

4*25*y^2-1*(100-4*x^2) = 0

4*x^2+100*y^2-100 = 0

(4*x^2+100*y^2-100)/4 = 0

(4*x^2+100*y^2-100)/4 = 0 // * 4

4*x^2+100*y^2-100 = 0

4*x^2 = -(100*y^2-100) // : 4

x^2 = (100-(100*y^2))/4

x^2 = (100-100*y^2)/4 // ^ 1/2

abs(x) = ((100-100*y^2)^(1/2))/2

x = ((100-100*y^2)^(1/2))/2 or x = -(((100-100*y^2)^(1/2))/2)

x in { ((100-100*y^2)^(1/2))/2, -(((100-100*y^2)^(1/2))/2) }

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